A steel wire of length $5$ m has a mass $0.1$ kg. If the wire has a tension of $800$ N, then wave velocity of wire in m $/$ s will be.

400 m / s

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200 m / s

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50 m / s

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100 m / s

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Solution

The correct option is B $200 m / s$
The linear mass density of wire is $m = \frac{01}{5} = 0.02 k g m^{- 1}$
Tension $=$ T $= 800$ N
The wave velocity is given by
$v = \sqrt{\frac{T}{m}}$
$= \sqrt{\frac{800}{0.02}} = \sqrt{4 \times 10^{4}}$
$= 2 \times 10^{2}$
$∴ v = 200 m / s$ .

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A steel wire of length 5m has a mass 0.1kg. If the wire has a tension of 800N, then wave velocity of wire in m/s will be.

The correct option is B 200m/sThe linear mass density of wire is m=015=0.02kgm−1Tension=T=800NThe wave velocity is given byv=√Tm=√8000.02=√4×104=2×102∴v=200m/s.

A steel wire of length $5$ m has a mass $0.1$ kg. If the wire has a tension of $800$ N, then wave velocity of wire in m $/$ s will be.

The correct option is B $200 m / s$
The linear mass density of wire is $m = \frac{01}{5} = 0.02 k g m^{- 1}$
Tension $=$ T $= 800$ N
The wave velocity is given by
$v = \sqrt{\frac{T}{m}}$
$= \sqrt{\frac{800}{0.02}} = \sqrt{4 \times 10^{4}}$
$= 2 \times 10^{2}$
$∴ v = 200 m / s$ .