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Question

A steel wire of mass 4.0 g and length 80 cm is fixed at the two ends. The tension in the wire is 50N. The frequency of the fourth harmonic of the fundamental is 



Your Answer
A

0.25 Hz

Your Answer
B

25 Hz

Correct Answer
C

250 Hz

Your Answer
D

none of these


Solution

The correct option is C

250 Hz


Given mass = 4g = 4 × 103 kg

length = 80 cm = 0.8 m

μ = masslength = 4 × 1030.8 = 0.5 × 102

given T = 50 N

Frequency of nth harmonic is given by fn = nv2L

v = Tμ = 500.5 × 102

=104 = 102ms1

f4 = 4 × 1022 × 0.8

= 0.25 × 103 = 250 Hz

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