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Displacement of COM:Application

A steel wire ...

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A steel wire of original length 1 m and cross-sectional area 4.0 mm is clamped at the two ends so that it lies horizontally and without tension. If a load of 2.16 kg is suspended from the middle point of the wire, what would be its vertical depression?Y f the steel 2.0 x 10" N m2. Take g-10 m s2

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Q. A steel wire of original length 1 m and cross-sectional area 4.00 mm² is clamped at the two ends so that it lies horizontally and without tensions. If a load of 2.16 kg is suspended from the middle point of the wire, what would be its vertical depression?
Y of the steel = 2.0 × 10¹¹ N m⁻². Take g = 10 m s⁻².

Q. A wire of length

L

is clamped at two ends so that it lies horizontally and without tension. A weight

W

is suspended from the middle point of the wire. The vertical depression is _______. (Young's modulus is

Y

1

kg weight is attached to one end of a steel wire if cross sectional area

3 m m^{2}

mm and young's modulus

10^{11} N / m^{2}

. The other end is suspended vertically from a hook on a wall, then the load is pulled horizontal and released. when the load passes through its lowest position the fractional change in length is

(g = 10 m / s^{2})

Q. A load of 4.0 kg is suspended from a ceiling through a steel wire of length 20 m and radius 2.0 mm. It is found that the length of the wire increases by 0.031 mm as equilibrium is achieved. Find Young modulus of steel. Take

g = 3.1 π m s^{- 2} .

Q. A mild steel wire of length 1.0 m and cross-sectional area 0.50 × 10¯² cm² is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.

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