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Hysteresis

A steel wire ...

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A steel wire of original length 1 m and cross-sectional area 4 mmsquare is clamped at the two ends so that it lies horizontally and without tension. If a load of 2. 16 kg is suspended from the middle point of the wire, what would be its vertical depression? Y of the steel = 2*10 power 11 Nm -2 and take g=10 ms-2

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A steel wire of original length 1 m and cross-sectional area $4.00 m m^{2}$ is clamped at the two ends so that it lies horizontally and without tension. If a load of 2.16 kg is suspended from the middle point of the wire, what would be its vertical depression ?

Y of the steel = $2.0 \times 10^{11} N m^{- 2} . T a k e g = 10 m s^{- 2}$ .

Q. A steel wire of original length 1 m and cross-sectional area

4.00 {m m}^{2}

is clamped at the two ends so that it lies horizontally and without tension. If a load of 2.16 kg is suspended from the middle point of the wire, what would be its vertical depression?Y of the steel

= 2.0 \times 10^{11} {N m}^{- 2}

= 10 {m s}^{- 2}

.

Q. A wire of length

L

is clamped at two ends so that it lies horizontally and without tension. A weight

W

is suspended from the middle point of the wire. The vertical depression is _______. (Young's modulus is

Y

Q. A light rod of length

2 m

is suspended from the ceiling horizontally by means of two vertical wires of equal length tied to its ends. One of the wires is made of steel and is of cross-section

0.1

{c m}^{2}

and the other of brass of cross-section

0.2 {c m}^{2}

. At which distance a weight may be hung along the rod, in order to produce equal strains in both the wires?

(Y_{s t e e l} = 2 \times 10^{11} N m^{- 2}, Y_{b r a s s} = 1 \times 10^{11} N m^{- 2})

Q. A mild steel wire of length 1.0 m and cross-sectional area 0.50 × 10¯² cm² is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.

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