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Standard XII

Physics

Thermal Expansion

A steel wire ...

Question

A steel wire of uniform cross - sectional area $2 m m^{2}$ is heated up to $50^{\circ}$ C and is stretched by clamping its two ends rigidly. The change in tension when the temperature falls from $50^{\circ}$ C to $30^{\circ}$ C is given by:
$α = 1.1 \times {10^{- 5}}^{\circ} C, Y = 2.0 \times 10^{11} \frac{N}{m^{2}}$

88 N

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$1.5 \times {2.0}^{10} N$

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$2.5 \times {2.0}^{10} N$

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Solution

The correct option is A
88 N

$T = y A α Δ T$

$= 2 \times 10^{11} \times 2 \times \times 10^{- 6} \times 1.1 \times 10^{- 5} \times (50 - 30)$

$= 88 N$

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Similar questions

Q. A steel wire of uniform cross - sectional area

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A steel wire of uniform cross - sectional area 2mm2 is heated up to 50∘ C and is stretched by clamping its two ends rigidly. The change in tension when the temperature falls from 50∘ C to 30∘C is given by: α=1.1×10−5∘C,Y=2.0×1011Nm2

The correct option is A 88 N T=yAαΔT =2×1011×2××10−6×1.1×10−5×(50−30) =88N

The correct option is A
88 N

$T = y A α Δ T$

$= 2 \times 10^{11} \times 2 \times \times 10^{- 6} \times 1.1 \times 10^{- 5} \times (50 - 30)$

$= 88 N$