A steering wheel of diameter $0.5 m$ is rotated anticlockwise by applying two forces each of magnitude $5 N$ . Calculate the moment of couple applied.

$2.0 N m$

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$2.5 N m$

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$4.5 N m$

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$4.0 N m$

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Solution

The correct option is B
$2.5 N m$

Diameter of a steering wheel = $0.5 m$

Radius = $\frac{d}{2}$ = $\frac{0.5}{2}$ = $0.25 m$

Magnitude of force = $5 N$

Moment of couple = $5 N$ $\times 0.25$ $m$ + $5 N \times 0.25 m$ = $2.5 N m$

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A steering wheel of diameter 0.5 m is rotated anticlockwise by applying two forces each of magnitude 5 N. Calculate the moment of couple applied.

The correct option is B 2.5 N m Diameter of a steering wheel = 0.5 m Radius = d2 = 0.52 = 0.25 m Magnitude of force = 5 N Moment of couple = 5 N ×0.25 m + 5N ×0.25m = 2.5 N m

A steering wheel of diameter $0.5 m$ is rotated anticlockwise by applying two forces each of magnitude $5 N$ . Calculate the moment of couple applied.

The correct option is B
$2.5 N m$

Diameter of a steering wheel = $0.5 m$

Radius = $\frac{d}{2}$ = $\frac{0.5}{2}$ = $0.25 m$

Magnitude of force = $5 N$

Moment of couple = $5 N$ $\times 0.25$ $m$ + $5 N \times 0.25 m$ = $2.5 N m$