A steering wheel of diameter 0.5 m is rotated anticlockwise by applying two forces each of magnitude 5 N. Calculate the moment of couple applied.

2.0 Nm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.5 Nm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4.5 Nm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.0 Nm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
2.5 Nm

Diameter of a steering wheel = 0.5 m

Radius = $\frac{d}{2}$ = $\frac{0.5}{2}$ = 0.25 m

Magnitude of force = 5 N

Moment of couple = 5 N $\times$ 0.5 m = 2.5 Nm

Suggest Corrections

Similar questions

Q. A steering wheel of diameter

0.5 m

is rotated anti-clockwise by applying two forces each of magnitude

5 N

. Calculate the moment of couple applied :

A steering wheel of diameter 0.5 m is rotated anticlockwise by applying two forces each of magnitude 5 N. Draw a diagram to show the application of forces and calculate the moment of the forces applied.

Q. A car with a steering wheel of radius

25 c m

is rotated with two anti-parallel forces of magnitude

5 N

each. Calculate the moment of the couple.

Q. A couple of 20 N-m is needed to rotate a steering wheel. What would be the magnitude of each force if the steering wheel’s diameter is 80 cm?

Explain how a steering wheel rotates with respect to couple.

Join BYJU'S Learning Program

A steering wheel of diameter 0.5 m is rotated anticlockwise by applying two forces each of magnitude 5 N. Calculate the moment of couple applied.

The correct option is B 2.5 Nm Diameter of a steering wheel = 0.5 m Radius = d2 = 0.52 = 0.25 m Magnitude of force = 5 N Moment of couple = 5 N × 0.5 m = 2.5 Nm

The correct option is B
2.5 Nm

Diameter of a steering wheel = 0.5 m

Radius = $\frac{d}{2}$ = $\frac{0.5}{2}$ = 0.25 m

Magnitude of force = 5 N

Moment of couple = 5 N $\times$ 0.5 m = 2.5 Nm