A steering wheel of diameter 0.5 m is rotated anticlockwise by applying two forces each of magnitude 5 N. Draw a diagram to show the application of forces and calculate the moment of couple applied.

Open in App

Solution

Moment of the force applied about $o = F \times R$
$= 5 N \times 0.25 m$
= 1.25Nm

Suggest Corrections

Similar questions

Q. A steering wheel of diameter

0.5 m

is rotated anti-clockwise by applying two forces each of magnitude

5 N

. Calculate the moment of couple applied :

A steering wheel of diameter $0.5 m$ is rotated anticlockwise by applying two forces each of magnitude $5 N$ . Calculate the moment of couple applied.

Q. A couple of 20 N-m is needed to rotate a steering wheel. What would be the magnitude of each force if the steering wheel’s diameter is 80 cm?

Q. A car with a steering wheel of radius

25 c m

is rotated with two anti-parallel forces of magnitude

5 N

each. Calculate the moment of the couple.

Q. A wheel of diameter

2 m

can be rotated about an axis passing through its centre by a moment of force equal to

2 \cdot 0 N m

. What the minimum force must be applied on its rim ?

Join BYJU'S Learning Program

A steering wheel of diameter 0.5 m is rotated anticlockwise by applying two forces each of magnitude 5 N. Draw a diagram to show the application of forces and calculate the moment of couple applied.

Moment of the force applied about o=F×R=5N×0.25m= 1.25Nm

Moment of the force applied about $o = F \times R$
$= 5 N \times 0.25 m$
= 1.25Nm