wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A step down DC chopper as shown in figure has a resistive load of R=15Ω and input voltage of 200 V. Voltage drop of chopper is 2.5 V and chopper frequency is 1 kHz. If the duty cycle is 50%, then the chopper efficiency is


A
98.74%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
49.37%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
95%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
69.83%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 98.74%
Rms current, I0r=α(VsVd)R
=0.5(2002.5)15
I0r=9.31A
Output power, Po=I20r×R
=9.312×15=1300.14
Input power Pf=1TT0Vsisdt
=1TαT0(VcVd)αTT×R
=Vs(VsVd)αTT×R
Pi=0.5×200×(2002.5)15
Pi=1316.67W
Efficiency, %η=P0Pi×100
=1300.141316.67×100
=98.74%

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Discontinuous Mode Analysis of Buck Regulator
OTHER
Watch in App
Join BYJU'S Learning Program
CrossIcon