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Transformer

A step down t...

Question

A step down transformer having efficiency of $75$ supplies $3$ ampere current at $120$ volt. Calculate the current in its primary coil, if it is operated at $440$ volt.

A

2

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B

1

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C

3

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D

4

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Solution

The correct option is B 1
We know efficiency $η = \frac{P_{o u t}}{P_{i n}}$
$η =$ .75
$P_{o u t}$ = $I_{0} V_{0}$
=3 $\times$ 120=360 W
$P_{i n} = \frac{P_{o u t}}{η} I_{s} V_{s} = \frac{P_{o u t}}{η} I_{s} = \frac{360}{0.75 \times 440} = 1.09 A$

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