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Question

A stone dropped from the top of a tower of height 125 m splashes into a pond of water at its base. When will the sound of the splash be heard at the top?
(Take velocity of sound = 340 ms1 and g = 10 ms2)


A

6.62 s

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B

5.368 s

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C

5.95 s

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D

6.79 s

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Solution

The correct option is B

5.368 s


Given, distance, s = 125 m, velocity of sound, v = 340 ms1 , g = 10 ms2

Time after which the splash is heard at the top is equal to the sum of the time t1 taken by the stone to fall down and the time t2 taken by the sound to travel from bottom to top.
Using, s=ut+12at2, where s = displacement, u = initial velocity, t = time, a = accelaration (here g)
We get, s=12gt21(since initial velocity,u = 0)
t1=2sg=2×12510t1 = 5 s
Again t2=height of towervelocity of sound
t2=125340=0.368 s
Total time =t1+t2=(5+0.368)s=5.368 s


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