A stone falling from the rest position under the influence of gravity. It strikes with a glass in time $t$ loses half of its velocity. If it then reaches the ground in $t$ seconds and gain velocity of $30 m / s$ . Find out time $t . (g = 10 m / s^{2})$

2 s

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3 s

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4 s

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5 s

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Solution

The correct option is A $2 s$
$v ⟹ \frac{g t}{2} + g t ⟹ \frac{3 g t}{2} ⟹ 30 m / s$

$30 \frac{t}{2} ⟹ 30$

$t = 2 s e c$

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A stone falling from the rest position under the influence of gravity. It strikes with a glass in time t loses half of its velocity. If it then reaches the ground in t seconds and gain velocity of 30m/s. Find out time t.(g=10m/s2)

The correct option is A 2sv⟹gt2+gt⟹3gt2⟹30m/s30t2⟹30t=2sec

A stone falling from the rest position under the influence of gravity. It strikes with a glass in time $t$ loses half of its velocity. If it then reaches the ground in $t$ seconds and gain velocity of $30 m / s$ . Find out time $t . (g = 10 m / s^{2})$

The correct option is A $2 s$
$v ⟹ \frac{g t}{2} + g t ⟹ \frac{3 g t}{2} ⟹ 30 m / s$

$30 \frac{t}{2} ⟹ 30$

$t = 2 s e c$