A stone falls from a balloon that is descending at a uniform rate of 12 m/s. The magnitude of the displacement of the stone from the point of release after 10 sec is

490 m

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510 m

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610 m

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725 m

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Solution

The correct option is C
610 m

u = -12m/s, g = - 9.8 m/ $s e c^{2}$ , t = 10sec

Displacement = $u t + \frac{1}{2} g t^{2}$

= $- 12 \times 10 + \frac{1}{2} \times - 9.8 \times 100 = - 610 m$ (since downwards)

The magnitude is 610m.

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A stone falls from a balloon that is descending at a uniform rate of 12 m/s. The magnitude of the displacement of the stone from the point of release after 10 sec is

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A stone falls from a balloon that is descending at a uniform rate of 12 m/s. The magnitude of the displacement of the stone from the point of release after 10 sec is

The correct option is C 610 m u = -12m/s, g = - 9.8 m/sec2, t = 10sec Displacement = ut+12gt2 = −12×10+12×−9.8×100=−610m (since downwards) The magnitude is 610m.

The correct option is C
610 m

u = -12m/s, g = - 9.8 m/ $s e c^{2}$ , t = 10sec

Displacement = $u t + \frac{1}{2} g t^{2}$

= $- 12 \times 10 + \frac{1}{2} \times - 9.8 \times 100 = - 610 m$ (since downwards)

The magnitude is 610m.