A stone falls from a balloon that is descending at a uniform rate of $12 m s^{- 1}$ . The displacement of the stone from the point of release after $10$ seconds is : ( $g = 9.8 m / s^{2}$ )

490 m

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510 m

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610 m

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725 m

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Solution

The correct option is C $610 m$
Here acceleration (a) will be gravity $= 9.8 m / s^{2}$
$u = 12 m / s$
time $= 10$ seconds
$S (d i s t a n c e) = u t + 0.5 a t \times t$
$= 12 \times 10 + 0.5 \times 9.8 \times 10 \times 10$
$= 120 + 0.5 \times 980$
$= 120 + 490$
$= 610$ meter
Hence,
option $C$ is correct answer.

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A stone falls from a balloon that is descending at a uniform rate of 12ms−1. The displacement of the stone from the point of release after 10 seconds is : (g=9.8m/s2)

The correct option is C 610mHere acceleration (a) will be gravity=9.8m/s2u=12m/stime=10 secondsS(distance)=ut+0.5at×t=12×10+0.5×9.8×10×10=120+0.5×980=120+490=610 meterHence,option C is correct answer.

A stone falls from a balloon that is descending at a uniform rate of $12 m s^{- 1}$ . The displacement of the stone from the point of release after $10$ seconds is : ( $g = 9.8 m / s^{2}$ )