A stone falls from a balloon that is descending at a uniform rate of $12 m s^{- 1}$ . The displacement of the stone from the point of release after 10 sec is :-

490 m

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610 m

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510 m

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725 m

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Solution

The correct option is D $610 m$
Given,
$u = 12 m / s$ , the velocity of the stone is same as ballon
$t = 10 s e c$
$g = 9.8 m s^{- 2}$
From 2nd equation of motion,
$s = u t + \frac{1}{2} g t^{2}$
$\Rightarrow s = 12 \times 10 + \frac{1}{2} \times 9.8 \times 10 \times 10$
$\Rightarrow s = 120 + 490$
$\Rightarrow s = 610 m$
The correct option is B.

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A stone falls from a balloon that is descending at a uniform rate of 12ms−1. The displacement of the stone from the point of release after 10 sec is :-

The correct option is D 610 mGiven,u=12m/s, the velocity of the stone is same as ballont=10 secg=9.8 ms−2From 2nd equation of motion,s=ut+12gt2⇒s=12×10+12×9.8×10×10⇒s=120+490⇒s=610mThe correct option is B.

A stone falls from a balloon that is descending at a uniform rate of $12 m s^{- 1}$ . The displacement of the stone from the point of release after 10 sec is :-