A stone falls from a cliff and travels $34.3 m$ in the last second before it reaches the ground. Calculate the height of the cliff.

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Solution

$S_{n t n} ⟹ u + \frac{a}{2} (2 n - 1)$
$S_{n t n} ⟹ \frac{a}{2} (2 n - 1)$
$a ⟹ g$
$\frac{7}{2} 34.3 ⟹ \frac{9.8}{2} (2 n 1)$
$2 n - 1 = 7$
$2 n = 8$
$n ⟹ 4$
$t ⟹ 4$
$S ⟹ h = \frac{1}{2} g t^{2}$
$= \frac{1}{2} \times 4.8 \times 4^{2}$
$⟹ 78.4 m$

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A stone falls from a cliff and travels 34.3m in the last second before it reaches the ground. Calculate the height of the cliff.

Sntn⟹u+a2(2n−1)Sntn⟹a2(2n−1)a⟹g7234.3⟹9.82(2n1)2n−1=72n=8n⟹4t⟹4S⟹h=12gt2=12×4.8×42⟹78.4m

A stone falls from a cliff and travels $34.3 m$ in the last second before it reaches the ground. Calculate the height of the cliff.

$S_{n t n} ⟹ u + \frac{a}{2} (2 n - 1)$
$S_{n t n} ⟹ \frac{a}{2} (2 n - 1)$
$a ⟹ g$
$\frac{7}{2} 34.3 ⟹ \frac{9.8}{2} (2 n 1)$
$2 n - 1 = 7$
$2 n = 8$
$n ⟹ 4$
$t ⟹ 4$
$S ⟹ h = \frac{1}{2} g t^{2}$
$= \frac{1}{2} \times 4.8 \times 4^{2}$
$⟹ 78.4 m$