A stone if dropped from tower.how long does it take to fall by 5m?find its acceleration after 2s of the fall.with what velocity does it strike the ground?( Take g as 10ms^-2

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Solution

Dear Student,

Given:

u=0 S= 5 m and g=10 m/s²

S=0.5gt² or t= 1 sec

Now velocity after 2 sec: v= gt = 20 m/s

acceleration = (20-0)/2 = 10 m/s2

To find final velcoity Height of tower needed:

Let it be of height H

Initial P.E=final Kinetic Energy

mgH=0.5mv²

v²= $\sqrt{2 g H}$

Regards.

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A stone if dropped from tower.how long does it take to fall by 5m?find its acceleration after 2s of the fall.with what velocity does it strike the ground?( Take g as 10ms^-2

Dear Student, Given: u=0 S= 5 m and g=10 m/s2 S=0.5gt2 or t= 1 sec Now velocity after 2 sec: v= gt = 20 m/s acceleration = (20-0)/2 = 10 m/s2 To find final velcoity Height of tower needed: Let it be of height H Initial P.E=final Kinetic Energy mgH=0.5mv2 v2=2gH Regards.

Dear Student,

Given:

u=0 S= 5 m and g=10 m/s²

S=0.5gt² or t= 1 sec

Now velocity after 2 sec: v= gt = 20 m/s

acceleration = (20-0)/2 = 10 m/s2

To find final velcoity Height of tower needed:

Let it be of height H

Initial P.E=final Kinetic Energy

mgH=0.5mv²

v²= $\sqrt{2 g H}$

Regards.