A stone is dropped from a balloon going up with a uniform velocity of 5m/s. If the balloon was 60 m high when the stone was dropped, find the height of balloon when the stone hits the ground. Take g=10m/s.
A
50 m
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B
60 m
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C
80 m
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D
100 m
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Solution
The correct option is C80 m
s=ut+12at2 ⇒−60=5(t)+12(−10)t2 ⇒−60=5t−5t2 ⇒5t2−5t−60=0 ⇒t2−t−12=0 ⇒t2−4t+3t−12=0 ⇒(t−4)(t+3)=0 ⇒t=4s Height of balloon from ground at this instant is h=60+(4)(5) ⇒h=80m