A stone is dropped from a cliff. Find its speed after the stone has fallen from 100 m. $(g = 9.8 m / s^{2})$

9.8 m/s

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19.6 m/s

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44.2 m/s

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24 m/s

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Solution

The correct option is C
44.2 m/s

It is a case of free fall under the gravity of the Earth. So the body would accelerate with 'g'.
Therefore, $v^{2}$ = $u^{2}$ + 2as (a = g)
$v^{2}$ = 0 + 2 $\times$ 9.8 $\times$ 100
$v^{2}$ = 1960
v = $\sqrt{1960}$ = 44.2 m/s

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A stone is dropped from a cliff. Find its speed after the stone has fallen from 100 m. (g=9.8m/s2)

The correct option is C 44.2 m/s It is a case of free fall under the gravity of the Earth. So the body would accelerate with 'g'. Therefore, v2​ = u2​ + 2as (a = g) v2​​ =​ 0 + 2 × 9.8 × 100 v2​​ = 1960 v = √1960 = 44.2 m/s

A stone is dropped from a cliff. Find its speed after the stone has fallen from 100 m. $(g = 9.8 m / s^{2})$

The correct option is C
44.2 m/s

It is a case of free fall under the gravity of the Earth. So the body would accelerate with 'g'.
Therefore, $v^{2}$ = $u^{2}$ + 2as (a = g)
$v^{2}$ = 0 + 2 $\times$ 9.8 $\times$ 100
$v^{2}$ = 1960
v = $\sqrt{1960}$ = 44.2 m/s