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Question

# A stone is dropped from a height h. Another stone is thrown up simultaneously from the ground, which can reach to maximum height of 4 h. The two stones will cross each other after time

A
h8g
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B
8gh
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C
2gh
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D
h2g
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Solution

## The correct option is A √h8gInitial velocity of 2nd stone. Using v2=u2+2as 0=u2−2g(4h) ⇒u2=√8gh Initial velocity of first stone is u1=0 Relative velocity u21=u2−u1=√8gh Initial relative distance between stones is drel=h Relative acceleration between stones is arel=−g−(−g)=0 Using t=drelurel t=h√8gh=√h8g

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