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Question

A stone is dropped from a height h. Another stone is thrown up simultaneously from the ground, which can reach to maximum height of 4 h. The two stones will cross each other after time

A
h8g
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B
8gh
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C
2gh
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D
h2g
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Solution

The correct option is A h8g
Initial velocity of 2nd stone.
Using v2=u2+2as
0=u22g(4h)
u2=8gh
Initial velocity of first stone is u1=0
Relative velocity u21=u2u1=8gh
Initial relative distance between stones is drel=h
Relative acceleration between stones is arel=g(g)=0
Using t=drelurel
t=h8gh=h8g

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