Question

A stone is dropped from a height of 125 m. If g $=$ 10 m s${}^{-2}$, what is the ratio of the distances travelled by it during the first and the last second of its motion?

Answer 1

$S_1=\frac{1}{2}\times g\times 1=5m$
$t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2\times 125}{10}}=5s$
$S_5=\frac{g}{2}\left(2\right(5)-1)$
$=9\times 5=45m$
$S_1:S_5=1:9$