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Question

A stone is dropped from a tower. It was found that it covered a distance of 45m during its last second of the fall. Calculate the time of the fall and the height of the tower? (g=10ms2)

A
5s,45m
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B
10s,90m
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C
5s,125m
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D
10s,100m
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Solution

The correct option is C 5s,125m
using eq of motion we have s=ut+(1/2)gt2
45=u1+(1/2)1012
u=455=40m/s
velocity at the bottom v2=u2+2gh
v2=402+21045
v2=2500m/s
Height of tower H=v22g=2500210=125m
time of fall t=2Hg=212510=5sec

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