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Standard XII

Physics

Work Energy Theorem Application

A stone is dr...

Question

A stone is dropped from the hill at the height of 180 meters. Calculate the time to reach the ground assume acceleration due to gravity is 10 $m / s^{2}$ and ignore air resistance.

3.0 s

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4.2 s

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6.0 s

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18 s

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36 s

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Solution

The correct option is B 6.0 s
Given : $S = 180$ m $u = 0 m / s$ $a = g = 10 m / s^{2}$
Using $S = u t + \frac{1}{2} a t^{2}$
$∴$ $180 = 0 + \frac{1}{2} \times 10 t^{2}$ $⟹ t = 6.0$ s

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A stone is dropped from the hill at the height of 180 meters. Calculate the time to reach the ground assume acceleration due to gravity is 10 m/s2 and ignore air resistance.

The correct option is B 6.0 sGiven : S=180 m u=0m/s a=g=10m/s2Using S=ut+12at2∴ 180=0+12×10t2 ⟹t=6.0 s

A stone is dropped from the hill at the height of 180 meters. Calculate the time to reach the ground assume acceleration due to gravity is 10 $m / s^{2}$ and ignore air resistance.

The correct option is B 6.0 s
Given : $S = 180$ m $u = 0 m / s$ $a = g = 10 m / s^{2}$
Using $S = u t + \frac{1}{2} a t^{2}$
$∴$ $180 = 0 + \frac{1}{2} \times 10 t^{2}$ $⟹ t = 6.0$ s