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Question

A stone is dropped from the top of a 20m high tower. 1sec later another stone is thrown downwards from the top. Both stone reach the ground simultaneously. If g is 10m/s2, initial velocity of second stone is


A
10m/s
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B
15m/s
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C
20m/s
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D
25m/s
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Solution

The correct option is B 15m/s
I dropped initial velocity =0
time will be given by h=12gt2
t=2hg=2×20 m10 m/s2=2 sec
II both reaches simultaneous be so ti,e taken by IInd stone will be
2 sec1 sec=1 sec
or t=1 sec
putting it in h=ut'+12gt2
& h=20 m,g=10m/s2
we get
20=u×1+5×1
u=15 m/s

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