A stone is dropped from the top of a 400m high tower. At the same time another stone is projected vertically upwards from the ground with a speed of 50m/s. The two stones will cross each other after a time
A
2s
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B
4s
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C
6s
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D
8s
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Solution
The correct option is D8s
S21=u21t+12a21t2
But a21=−g−(−g)=0ms−2 ⇒+400=[50−0]t⇒t=8s