A stone is dropped from the top of a building 147 m high. How long will it take to reach the ground? What will be its velocity when it strikes the ground?

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Solution

$h = 147 m$
$h = \frac{1}{2} g t^{2} \Rightarrow t = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 147}{9.8}} = 5.4772258 s$
$v = \sqrt{2 g h} = \sqrt{2 \times 9.8 \times 147} = 53.6768106 ㎧$

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A stone is dropped from the top of a building 147 m high. How long will it take to reach the ground? What will be its velocity when it strikes the ground?

h=147mh=12gt2⇒t=√2hg=√2×1479.8=5.4772258sv=√2gh=√2×9.8×147=53.6768106㎧

$h = 147 m$
$h = \frac{1}{2} g t^{2} \Rightarrow t = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 147}{9.8}} = 5.4772258 s$
$v = \sqrt{2 g h} = \sqrt{2 \times 9.8 \times 147} = 53.6768106 ㎧$