A stone is dropped into a lake from a tower 500 metre high. Taking the speed of sound as 330 m/s, the sound of the splash will be heard by the man approximately after

11.5 seconds

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

21 seconds

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 seconds

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14 seconds

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
11.5 seconds

$t$ = $\sqrt{\frac{2 h}{g}} + \frac{h}{v}$

Substituting the values, we get, t=11.5 second.

Suggest Corrections

Similar questions

A stone is dropped into a lake from a tower 500 metre high. Taking the speed of sound as 330 m/s, the sound of the splash will be heard by the man approximately after

Q. A stone is dropped into a lake from a tower

500

metre high. The sound of splash will be heard by the man approximately after:

A stone is dropped into a lake from a tower 500 m high. The sound of the splash will be heard by a man on the tower after :

[Assume speed of sound = 330 m/s; g = 10 m/s

^{2}

]

Q. A man dropped a stone into a lake from a tower

500 m

high. The sound of the splash will be heard by the man approximately after (take

g = 10 m / s^{2}

and speed of sound in air to be

340 m / s

)

Join BYJU'S Learning Program

A stone is dropped into a lake from a tower 500 metre high. Taking the speed of sound as 330 m/s, the sound of the splash will be heard by the man approximately after

The correct option is A 11.5 seconds t = √2hg + hv Substituting the values, we get, t=11.5 second.

The correct option is A
11.5 seconds

$t$ = $\sqrt{\frac{2 h}{g}} + \frac{h}{v}$

Substituting the values, we get, t=11.5 second.