A stone is dropped into a well $44.1 m$ deep. The splash is heard $3.13 s$ after the stone is dropped. Find the velocity of sound in air. Take $g = 9.8 m / s^{2}$ .

319.2 m / s

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329.2 m / s

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339.2 m / s

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349.2 m / s

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Solution

The correct option is B $339.2 m / s$
For downward motion of the stone:
$s = u t + (1 / 2) a t^{2}$
$44.1 = (1 / 2) \times 9.8 \times t_{1}^{2}$
$t_{1} = 3 s$

For reflected sound wave:
$d = v t$
$44.1 = v (3.13 - 3)$
$v = 339.23 m / s$

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