Question

a stone is projected from ground with velocity of 20root2 m/s at an angle of 45 with the horizontal . find the maximum height from the ground attained by stone ?

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{maximum}\mathrm{height},\mathrm{H}=\frac{{\mathrm{u}}^2{\sin }^2\mathrm{\theta }}{2\mathrm{g}} \\ \mathrm{H}=\frac{{\left(20\sqrt{2}\right)}^2{\sin }^{2}45°}{2\times 9.8} \\ \mathrm{H}=\frac{800\times {\left({\displaystyle \raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$\sqrt{2}$}\right.}\right)}^2}{19.6} \\ \mathrm{H}=\frac{400}{19.6}=20.4\mathrm{m} \end{gathered}$$