A stone is projected vertically upwards with a velocity of 20m/s. if the stone reaches a hight of n meters find the value of n taking the acceleration due to gravity to be 10m/s

Open in App

Solution

Dear Student ,
Here in this case the initial velocity is u =20 m/s
Final velocity is v =0
So let us take that time taken is 't' .
So , from equation of motion we can write that ,
v = u -gt
or , u = gt
or , t = u /g = 20/10 = 2 s
So the height acquired by the stone in 2 s is ,
h = ut - 1/2gt² = 40 - 20 = 20 m
or , n = 20 m
Regards

Suggest Corrections

Similar questions

Q. Rohan throws a stone vertically upwards with a velocity of 40 m/s. Assuming no air resistance, find the displacement covered by the stone in the fourth second of its motion, given that the acceleration due to gravity, g is 10 m/s

^{2}

A ball thrown vertically upwards with a speed of $20 m / s$ from the top of a tower reaches a certain height and then falls back to the earth in $6 s .$ Find the height of the tower. [Take acceleration due to gravity, $g = 10 m / s^{2}$ ]

Q. A stone dropped from the top of a tower reaches the ground with a velocity of 58.8 m/s in 6 seconds. Calculate the value of acceleration due to gravity.

A stone is thrown in a vertically upward direction with a velocity of 5 m s⁻¹. If the acceleration of the stone during its motion is 10 m s⁻² in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Q. A stone projected vertically upwards reaches to the level of window

10 m

from the ground. Find the magnitude of the velocity of the stone at the time of its projection.

Join BYJU'S Learning Program