Question

A stone is projected with speed of 50 m/s at an angle of ${60}^0$ with the horizontal.The speed of the stone at highest point of trajectory is

• A. 75 m/s
• B. 25 m/s
• C. 50 m/s
• D. Cannot find

Answer 1

The correct option is B 25 m/s

At the highest point, the stone has only horizontal velocity but not vertical velocity.

Initial horizontal velocity of stone $u_x=u\cos \theta =50\times \cos 60=25m/s$

Since, there is no acceleration in the horizontal direction. so horizontal velocity of stone remains constant with time.

Thus, speed at the highest point $V_x=u_x=25m/s$