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Question

A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity.

A
29.6 ms1
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B
19.6 ms1
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C
20.6 ms1
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D
20.8 ms1
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Solution

The correct option is B 19.6 ms1
According to the equation of motion under gravity:
v2u2=2 gs
Where,
u = initial velocity of the stone
v = final velocity of the stone
s = height of the stone
g = acceleration due to gravity
Here, u = 0, s = 19.6 m and g = 9.8 ms2
v202=2×9.8×19.6
v2=2×9.8×19.6=384.16
v=19.6 ms1
Hence, the velocity of the stone just before touching the ground is 19.6 ms1

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