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Standard XII

Physics

Periodic Motion

A stone is sw...

Question

A stone is swinging in a horizontal circle $0.8 m$ in diameter at $30 r e v / m i n$ . A distant horizontal light beam causes a shadow of the stone to be formed on a nearly vertical wall. The amplitude and period of the simple harmonic motion for the shadow of the stone are

0.4 m

4 s

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0.2 m

2 s

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0.4 m

2 s

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0.8 m

2 s

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Solution

The correct option is C $0.4 m$ , $2 s$
$ω = \frac{2 π}{T}$
$ω = 2 π n$
$T = 2 s e c o n d s$
$r = \frac{d}{2}$
$r = A (a m p l i t u d e)$
$d = 0.8 m$
$r = A = 0.4 m$

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A stone is swinging in a horizontal circle 0.8 m in diameter at 30 rev/min. A distant horizontal light beam causes a shadow of the stone to be formed on a nearly vertical wall. The amplitude and period of the simple harmonic motion for the shadow of the stone are

The correct option is C 0.4m, 2sω=2πTω=2πnT=2secondsr=d2r=A(amplitude)d=0.8mr=A=0.4m

A stone is swinging in a horizontal circle $0.8 m$ in diameter at $30 r e v / m i n$ . A distant horizontal light beam causes a shadow of the stone to be formed on a nearly vertical wall. The amplitude and period of the simple harmonic motion for the shadow of the stone are

The correct option is C $0.4 m$ , $2 s$
$ω = \frac{2 π}{T}$
$ω = 2 π n$
$T = 2 s e c o n d s$
$r = \frac{d}{2}$
$r = A (a m p l i t u d e)$
$d = 0.8 m$
$r = A = 0.4 m$