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Question

# A stone is thrown from a point at a distance a from a wall of height b. If it just clears the wall and angle of projection is α, the maximum height attained by the stone is

A
a2sec2α4(asecαb)
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B
a2tan2α4(atanαb)
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C
a2tanα4(absecα)
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D
a2tanα4
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Solution

## The correct option is B a2tan2α4(atanα−b)Equation of trajectory of the projectile is given by, y=xtanα−(gx2)2u2cos2α Height of wall, y=b and distance between wall and point of projection, x=a, therefore b=atanα−ga22u2cos2α ⇒atanα−b=ga22u2cos2α therefore, u2g=a22cos2α(atanα−b) Maximum height, h=u2sin2α2g ⇒h=a2tan2α4(atanα−b)

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