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Question

# A stone is thrown in a vertically upward direction with a velocity of 6 msâˆ’1. If the acceleration of the stone during its motion is 12 msâˆ’2 in the downward direction, what will be the height attained by the stone?

A
1.5 m
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B
1.2 m
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C
0.25 m
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D
0.5 m
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Solution

## The correct option is A 1.5 mu = 6 ms−1 v = 0 a = −12 ms−2 s = ? t = ? From the first equation of motion, v = u + at 0 = 6 + (-12)t -6 = -12t t = 612 = 0.5 s From the third equation of motion, v2 - u2 = 2as (0)2 - (6)2 = 2 × (-12) × s - 36 = - 24 × s s = 3624 = 1.5 m

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