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Question

A stone is thrown in vertically upward direction with a velocity of 5 msāˆ’1. If the acceleration of the stone during its motion is 10 msāˆ’2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

A
Height=1.25m and time =0.5s
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B
Height=2.5m and time =0.5s
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C
Height=2.5m and time =0.05s
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D
Height=1.25m and time =0.05s
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Solution

The correct option is A. Height=1.25m and time =0.5s

Given, initial velocity, u=5ms1
Final velocity, v=0
Since, u is upward & a is downward, it is a retarded motion.
a=10 ms2
Height attained by stone, s=?
Time take to attain height, t=?
(i) Using the relation, v2u2=2as, we have
s=v2u22a
=(0)2(5)22×(10)=1.25m
(ii) Using the relation, v=u+at
0=5+(10)t or
t=5/10=0.5s

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