The correct option is C 5v2o8g
Velocity of particle will become zero in time,
to=vog (by using first equation of motion)
The given time t=1.5vog is greater than the time to=vog
Hence, The total distance travelled will be the sum of the distance travelled in time to and (t−to)
Distance travelled =st+st−to
By using third equation of motion, 02=v2o−2gst
st=v2o2g
For st−t0, using second equation of motion, st−to=(0×t)+12g(t−to)2
st−to=12g(1.5vog−vog)2
st−to=12g(.5vo)2
st−to=v2o8g
Distance travelled =v2o2g+v2o8g⇒5v2o8g