wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A stone is thrown vertically upward with an initial velocity vo. The distance travelled in time 1.5vog is

A
v2o2g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3v2o8g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5v2o8g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 5v2o8g
Velocity of particle will become zero in time,
to=vog (by using first equation of motion)
The given time t=1.5vog is greater than the time to=vog
Hence, The total distance travelled will be the sum of the distance travelled in time to and (tto)
Distance travelled =st+stto
By using third equation of motion, 02=v2o2gst
st=v2o2g
For stt0, using second equation of motion, stto=(0×t)+12g(tto)2
stto=12g(1.5vogvog)2
stto=12g(.5vo)2
stto=v2o8g
Distance travelled =v2o2g+v2o8g5v2o8g

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Free Fall
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon