A stone is thrown vertically upwards and the heights $x$ ft. reached by the stone in $t$ seconds is given by $x = 80 t - 16 t^{2}$ . The stone reaches the maximum height in

2

seconds

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2.5

seconds

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3

seconds

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1.5

seconds

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Solution

The correct option is B $2.5$ seconds
Height travelled is given by $x = 80 t - 16 t^{2}$
Maximum height travelled is given when $\frac{d x}{d t} = 0 \Rightarrow 80 - 32 t = 0 \Rightarrow t = 2.5$
at $t = 2.5 s e c$ stone reaches its maximum height.

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A stone is thrown vertically upwards and the heights x ft. reached by the stone in t seconds is given by x=80t−16t2. The stone reaches the maximum height in

The correct option is B 2.5 secondsHeight travelled is given by x=80t−16t2Maximum height travelled is given when dxdt=0⇒80−32t=0⇒t=2.5at t=2.5sec stone reaches its maximum height.

A stone is thrown vertically upwards and the heights $x$ ft. reached by the stone in $t$ seconds is given by $x = 80 t - 16 t^{2}$ . The stone reaches the maximum height in

The correct option is B $2.5$ seconds
Height travelled is given by $x = 80 t - 16 t^{2}$
Maximum height travelled is given when $\frac{d x}{d t} = 0 \Rightarrow 80 - 32 t = 0 \Rightarrow t = 2.5$
at $t = 2.5 s e c$ stone reaches its maximum height.