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Question

A stone is thrown vertically upwards. When the stone is at a height equal to half of its maximum height its speed will be 10 m/s, then the maximum height attained by the stone is (Take g =10 m/s2)

A
3 m
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B
15 m
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C
1 m
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D
10 m
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Solution

The correct option is D 10 m
Let u be the initial velocity and h be the maximum height attained by the stone.
v21=u22gh,
(10)2=u22×10×h2
100=u210h ....(i)
Again at height h,
v22=u22gh
(0)2=u22×10×h
u2=20h ... (ii)
So, from Eqs. (i) and (ii) we have
100=10h
h=10m

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