A stone is tied to the middle of a string and suspended from one end as shown in the figure. Here S is the stone and O is the pint of suspension. (ii) if we increase the pull at P gradually, the string will break
A
Below the stone
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B
At the point P itself
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C
Above the stone
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D
Nothing can be decided
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Solution
The correct option is C Above the stone
If free end of the string P is given a sufficient sharp jerk then string break at point O below the stone mass.
We know that the hole mass is suspendent and the point above the stone has the most weight to support, because inertia of string mass will limit the strain imposed on the string above it. if we apply force slowly then stone has to goes down and maintain inertia support above.
But if we applied sharp jerk it is like a impulsive force, (Ft) is impulse where t is very small the stone has goes down in this small time and therefore the point below the stone faced maximum strain and it break.
if we applied force and increase gradually then the stone adjusted itself and maintain its own weight or whole weight support at point above the stone.
therefore the point above the stone acquire force applied f weight support but below the stone every point support applied force and weight of stone but not hole weight therefore string break above the stone. in this case.