A stone of mass 0-1kg tied to one end of a string 1-0m long is revolved in a horizontal circle at the rate of 10- revolution per second- Calculate the tension of the string-

The correct option is B 40N #10; #10; amp;[ #10;m=0.1 kg; #10;γ=1 m; #10;ω=10 / π× 2 πrad / s; #10;ω=20 rad / ...

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Standard XII

Physics

Surface Tension

A stone of ma...

Question

A stone of mass $0.1 k g$ tied to one end of a string $1.0$ m long is revolved in a horizontal circle at the rate of $10 / π$ revolution per second. Calculate the tension of the string?

30 N

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40 N

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50 N

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60 N

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Solution

The correct option is B $40 N$
$\begin{matrix} \begin{matrix} m = 0.1 k g γ = 1 m ω = 10 / π \times 2 π r a d / s ω = 20 r a d / s \end{matrix} on Tension, I = m ω^{2} r \begin{matrix} on T = 0.1 \times 400 \times 1 on T = 40 N \end{matrix} \end{matrix}$

Option B

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A stone of mass 0.1kg tied to one end of a string 1.0m long is revolved in a horizontal circle at the rate of 10/π revolution per second. Calculate the tension of the string?

The correct option is B 40Nm=0.1 kgγ=1 mω=10/π×2πrad/sω=20rad/s on Tension, I=mω2r on T=0.1×400×1 on T=40 N Option B

A stone of mass $0.1 k g$ tied to one end of a string $1.0$ m long is revolved in a horizontal circle at the rate of $10 / π$ revolution per second. Calculate the tension of the string?

The correct option is B $40 N$
$\begin{matrix} \begin{matrix} m = 0.1 k g γ = 1 m ω = 10 / π \times 2 π r a d / s ω = 20 r a d / s \end{matrix} on Tension, I = m ω^{2} r \begin{matrix} on T = 0.1 \times 400 \times 1 on T = 40 N \end{matrix} \end{matrix}$

Option B