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Question

# A stone of mass 10kg tied with a string of length 0.5m is rotated in a vertical circle. Find the total energy of the stone at the highest position. (in J)

A
123.36
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B
122.5
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C
154.3
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D
185.6
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Solution

## The correct option is B 122.5assume that potential energy at lowest point is zero and stone is rotating with critical velocityso the magnitude of velocity at highest point is v=√gl where l=length of stringtotal energy E=K.E.+P.E.⇒K.E.=12mv2=1210×(√9.8×0.5)2=24.5JP.E.=mgh=mg(2l)=10×9.8×(2×0.5)=98Jso the total energy E=98+24.5=122.5J

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