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Standard XII

Physics

Perfectly Elastic Collision

A stone of ma...

Question

A stone of mass $2$ kg is tied to a string of length $0.5$ m it the breaking tension of the string is $900$ N then the maximum angular velocity the stone can have in uniform circular motion is

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Solution

m=2kg T=mlw2
l=0.5 900=2 x 0.5w2
T=900 w=30
w=30 rad s-1

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A stone of mass 2 kg is tied to a string of length 0.5 m it the breaking tension of the string is 900 N then the maximum angular velocity the stone can have in uniform circular motion is

m=2kg T=mlw2l=0.5 900=2 x 0.5w2T=900 w=30w=30 rad s-1

A stone of mass $2$ kg is tied to a string of length $0.5$ m it the breaking tension of the string is $900$ N then the maximum angular velocity the stone can have in uniform circular motion is

m=2kg T=mlw2
l=0.5 900=2 x 0.5w2
T=900 w=30
w=30 rad s-1