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Question

A stone of mass 2 kg is projected from ground with speed 20 m/s at angle 30 with horizontal. The centripetal force acting on the object 1 s after projection is

A
10 N
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B
20 N
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C
30 N
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D
40 N
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Solution

The correct option is B 20 N
To find v:
vx=ux=103 m/s
vy=uygt=usinαgt
vy=20sin3010=0
So, at t=1 s particle is at maximum height and velocity is horizontal.

Force acting perpendicular to velocity at this instant is mg. This contributes to centripetal force.

Fc=mg=20 N

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