A stone of mass 2kg is projected from ground with speed 20m/s at angle 30∘ with horizontal. The centripetal force acting on the object 1s after projection is
A
10N
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B
20N
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C
30N
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D
40N
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Solution
The correct option is B20N
To find v: vx=ux=10√3m/s vy=uy−gt=usinα−gt vy=20sin30∘−10=0
So, at t=1s particle is at maximum height and velocity is horizontal.
Force acting perpendicular to velocity at this instant is mg. This contributes to centripetal force.