A stone of mass 2kg is tied to a string of length 0.5m. If the breaking tension of the string is 900N, then the maximum angular velocity, the stone can have in uniform circular motion is:

30 rad/s

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20 rad/s

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10 rad/s

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40 rad/s

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Solution

The correct option is A
30 rad/s

$T - m g = m ω^{2} l 900 - 2 \times 10 = 2 ω^{2} \times 0.5 ω^{2} = 880 ω = 29.66 ω = 30 r a d / s e c$

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A stone of mass 2kg is tied to a string of length 0.5m. If the breaking tension of the string is 900N, then the maximum angular velocity, the stone can have in uniform circular motion is:

The correct option is A 30 rad/s T−mg=mω2l900−2×10=2ω2×0.5ω2=880ω=29.66ω=30rad/sec

The correct option is A
30 rad/s

$T - m g = m ω^{2} l 900 - 2 \times 10 = 2 ω^{2} \times 0.5 ω^{2} = 880 ω = 29.66 ω = 30 r a d / s e c$