A stone of mass 5 Kg is thrown upwards with a speed of 36 m-sec- With what speed earth recoil- Mass of the earths 6-1024 Kg assuming that there is no external force on the system

Given, #10; #10;Momentum of earth, =MV #10; #10;Momentum of stone, =mv #10; #10;From conservation of momentum #10; #10;Initial mom ...

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Standard XII

Physics

Momentum

A stone of ma...

Question

A stone of mass $5 K g$ is thrown upwards with a speed of $36 m / s e c$ . With what speed earth recoil. Mass of the earths $6 \times 10^{24} K g$ (assuming that there is no external force on the system)

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Solution

Given,

Momentum of earth, $= M V$

Momentum of stone, $= m v$

From conservation of momentum

Initial momentum = final momentum

$0 = M V + m v$

$V = \frac{- m v}{M} = \frac{- 5 \times 36}{6 \times 10^{24}} = 3 \times 10^{- 23} m / s$

Recoil velocity of earth is $3 \times 10^{- 23} m / s$

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A stone of mass 5 Kg is thrown upwards with a speed of 36 m/sec. With what speed earth recoil. Mass of the earths 6×1024 Kg (assuming that there is no external force on the system)

Given, Momentum of earth, =MV Momentum of stone, =mv From conservation of momentum Initial momentum = final momentum 0=MV+mv V=−mvM=−5×366×1024=3×10−23 m/s Recoil velocity of earth is 3×10−23m/s

A stone of mass $5 K g$ is thrown upwards with a speed of $36 m / s e c$ . With what speed earth recoil. Mass of the earths $6 \times 10^{24} K g$ (assuming that there is no external force on the system)

Given,

Momentum of earth, $= M V$

Momentum of stone, $= m v$

From conservation of momentum

Initial momentum = final momentum

$0 = M V + m v$

$V = \frac{- m v}{M} = \frac{- 5 \times 36}{6 \times 10^{24}} = 3 \times 10^{- 23} m / s$

Recoil velocity of earth is $3 \times 10^{- 23} m / s$