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Question

A stone of mass 5 kg is tied to a string of length 2.5 m, is whirled round in a horizontal circle. What is the maximum angular velocity with which the stone can be whirled around, if the string can withstand a maximum tension of 1250 N ?

A
30 rad/s
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B
20 rad/s
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C
10 rad/s
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D
5 rad/s
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Solution

The correct option is C 10 rad/s
It is given that the breaking tension of string (Tmax)=1250 N.

To find maximum angular velocity ωmax:
Tmax=mlω2max
where (l) is length of the string.

ω2max=Tmaxml
ωmax=Tmaxml=  12505×52=250025=100=10 rad/s

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