Question

A stone of mass m at the end of a string of length I is whirled in a vertical circle at a constant speed. The tension is the string will be maximum when the stone is

• A. At the top of the circle
• B. Half way down from the top
• C. Quarter way down from the top
• D. At the bottom of the circle

Answer 1

The correct option is D

At the bottom of the circle

Considering dynamic equilibrium

$T_1=mg+\frac{m{V}^2}{r}$
$T_2=\frac{m{V}^2}{r}-mg$

$\therefore T_1>T_2$
Maximum tension will be at the bottom of the circle