wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A stone of mass m is tied to a string and is moved in a vertical circle of radius R making f revolutions per minute. The total tension in the string when the stone is at its lowest point is

A
m(g+f2R2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
m(g+πfR2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
m(g+πfR)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
m{g+(π2f2R)900}
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D m{g+(π2f2R)900}
Tension at lowest point T=mg+mω2R=mg+m4π2f2R
If n is revolution per minute then T=mg+m4π2f23600R=mg+mπ2f2R900

flag
Suggest Corrections
thumbs-up
10
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed and Velocity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon