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Question

A stone of mass m tied to a string of length l is rotating along a circular path with constant speed v. What will be the torque on the stone?


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Solution

Step 1: Given:

Stone mass = m

string of length = l

velocity = V

Step 2: Formula

Torque is given byτ=r×F=r×mv2r

a is acceleration.

r is the axle radius.

v is the speed.

m is the mass of stone.

Step 3: Solution

As the direction of centripetal force and position vector is directed toward center

T=r×F=rFsinθhereθ=0oThereforeT=0

The torque will be zero.


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